1 solutions

  • 1
    @ 2025-8-6 21:44:09

    #include <bits/stdc++.h> using namespace std; int n, k, a[100005], sum; int main() { cin >> n >> k; for (int i = 1;i <= n;i++) { cin >> a[i]; } for (int i = 1;i <= min(10, k);i++) { for (int j = 1;j <= n;j++) { a[j] = ceil(sqrt(a[j]) * 10); } } for (int i = 1;i <= n;i++) { sum += a[i]; } double x = sum, y = n; cout << fixed << setprecision(2) << x / y; return 0; }

    • 1

    Information

    ID
    1084
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    8
    Tags
    (None)
    # Submissions
    76
    Accepted
    13
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