先将7天对应的颜色赋值给一个数组（a），然后进行n次循环。每次循环都输入一次颜色（s）和天数（k），并把a数组遍历一遍，如果a数组当前下标位置等于s，就输出a[(j(下标)+k+1)%7]。

using namespace std;
int n, k;
string s, a[7] = {"Purple", "Red",  "Orange", "Yellow", "Green", "Blue", "Cyan"};
int main()
{
	cin >> n;
	for (int i = 1;i <= n;i++)
	{
		cin >> s >> k;
		for (int j = 0;j < 7;j++)
		{
			if (a[j] == s)
			{
				cout << a[(j + k + 1) % 7] << endl;
			}
		}
	}
	return 0;
}

#include <bits/stdc++.h>
using namespace std;
int n, k;
string s, a[7] = {"Purple", "Red",  "Orange", "Yellow", "Green", "Blue", "Cyan"};
int main()
{
	cin >> n;
	for (int i = 1;i <= n;i++)
	{
		cin >> s >> k;
		for (int j = 0;j < 7;j++)
		{
			if (a[j] == s)
			{
				cout << a[(j + k + 1) % 7] << endl;
			}
		}
	}
	return 0;
}