2 solutions

  • 0
    @ 2025-9-1 19:11:48
    #include<bits/stdc++.h>
    using namespace std;
    int main(){
        int n,m,t=1,a[1000][1000],b=1,k,j;
        cin>>n>>m>>k;
        for(int i=1;i<=m;i++){
            if(t%2!=0){
                for(j=1;j<=n;j++){
                    a[i][j]=b;
                    b++;
                }
            }
            else if(t%2==0){
                for(j=n;j>=1;j--){
                    a[i][j]=b;
                    b++;
                }
            }
            if(a[n][m]==k){
                cout<<i<<" "<<j;
                break;
            }
            t++;
        }
        return 0;
    }
    ```
    
    
    ```
    • 0
      @ 2025-8-29 16:30:32

      • 1

      Information

      ID
      1009
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      9
      Tags
      # Submissions
      79
      Accepted
      9
      Uploaded By