3 solutions
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1
#include <bits/stdc++.h> using namespace std; int n, a[35][35]; int main() { cin >> n; for (int i = 1;i <= n;i++) { for (int j = 1;j <= n;j++) { cin >> a[i][j]; } } for (int i = 1;i <= n;i++) { for (int j = 1;j <= n;j++) { cout << a[i][j] - a[j][i] << " "; } cout << endl; } return 0; }
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0
#include<bits/stdc++.h> using namespace std; int main(){ int a[100][100],b[100][100],c[100][100],n; cin>>n; for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ cin>>a[i][j]; b[i][j]=a[i][j]; } } for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ c[i][j]=a[i][j]-b[j][i]; cout<<c[i][j]<<" "; } cout<<endl; } return 0; }
- 1
Information
- ID
- 1076
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 7
- Tags
- (None)
- # Submissions
- 56
- Accepted
- 14
- Uploaded By