2 solutions

  • 1
    @ 2025-8-26 13:57:17
    
    #include<bits/stdc++.h>
    using namespace std;
    int main(){
        int n,a,ans=0;
        cin>>n;
        for(int i=1;i<=2*n-1;i++){
            cin>>a;
            ans^=a;
        }
        cout<<ans;
        return 0;
    }
    
    • 1
      @ 2025-8-14 17:10:36
      int n,res,tmp
      输入n.
      输入res.
      循环进行异或消除;
      输出消除后的res;
      #include<bits/stdc++.h>
      using namespace std;
      int main(){
       int n,res,tmp;
       cin>>n;
       cin>>res;
       for(int i=2;i<=2*n-1;i++){
      	cin>>tmp;
      	res^=tmp;
       }
       cout<<res;
      return 0;
      }
      
      • 1

      Information

      ID
      1088
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      7
      Tags
      (None)
      # Submissions
      77
      Accepted
      15
      Uploaded By