2 solutions
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0
#include<bits/stdc++.h> using namespace std; int main(){ int n,m,t=1,a[1000][1000],b=1,k,j; cin>>n>>m>>k; for(int i=1;i<=m;i++){ if(t%2!=0){ for(j=1;j<=n;j++){ a[i][j]=b; b++; } } else if(t%2==0){ for(j=n;j>=1;j--){ a[i][j]=b; b++; } } if(a[n][m]==k){ cout<<i<<" "<<j; break; } t++; } return 0; } ``` ```
Information
- ID
- 1009
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 9
- Tags
- # Submissions
- 79
- Accepted
- 9
- Uploaded By