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  • 0
    @ 2025-9-17 18:14:54
    
    

    #include<bits/stdc++.h> using namespace std; int main() { int n; string a; cin>>n>>a; for(int i=0;i<a.size();i++){ a[i]='a'+(a[i]-'a'+n)%26; } cout<<a; return 0; }

    【深基6.例2】小书童——凯撒密码(caesar)

    Information

    ID
    101
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    7
    Tags
    # Submissions
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    Accepted
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