3 solutions

  • 0
    @ 2025-8-28 16:45:32
    
    #include<bits/stdc++.h>
    using namespace std;
    int main() {
    int n;
    string m;
    cin>>n>>m;
    for(int i=0;i<m.size();i++){
        m[i]='a'+(m[i]-'a'+n)%26;
    }
    cout<<m;
        return 0;
    }
    

    【深基6.例2】小书童——凯撒密码(caesar)

    Information

    ID
    101
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    7
    Tags
    # Submissions
    76
    Accepted
    15
    Uploaded By