2 solutions
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0
int n; 输入n; 数组a minx存储; 循环输入a[i]; 不断比较; 输出 #include<bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; int a[100000]; int minx=0; for(int i=0;i<n;i++){ cin>>a[i]; if(a[i]<a[minx]){ minx=i; } } for(int i=0;i<n;i++){ if(a[i]==a[minx]){ cout<<i+1<<" "; } } return 0; }
Information
- ID
- 1007
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 7
- Tags
- # Submissions
- 47
- Accepted
- 12
- Uploaded By